Pointers And Structures

Pointers And Structures

 We know that the name of an array stands for the address of

its zeroth element.The same thing is true of the names of  arrays of structure variables.Suppose product is an array variable of structtype.The name product represents the address of its zeroth element consider the following declaration.

  struct inventory
  {
     char name[30];
     int number;
     float price;
  }
  product[2],*ptr;
 This statement declares product s an array of two elements,each of the type struct inventory and ptr as a pointer to data objects of the type struct inventory.



  The assignment  ptr=product;   would assign the address of the zeroth element of product
to ptr.This is,the pointer ptr will now point to product[0].Its members can be accessed using the following notation.
 
     ptr --> name
     ptr--> number
     ptr --> price
    The symbol -->is called the arrow operator and is made up of a minus sign and a greater than sign.Note that ptr--> is simply another way f wrting product[0].When the pointer ptr is incremented by one,it is made to point to the next  record. i.e,product[1]. We could use the notation
(*ptr).number   to access the member number.The parantheses around *ptr are necessary because the member operator "." has a higher precedence than the operator *

  A program to illustrate the use of a structure pointer to manipulate the elements of an array of structures the program highlights all the features discussed above.Note that the pointer ptr(of type struct invert) is also used as the loop control index in for loops

struct invent
{
    char *name[20];
    int number;
    float price;
};
  main( )
  {
    struct invent product[3],*ptr;
    printf("INPUT\n\n");
    for(ptr=product;ptr lessthan product+3;ptr++)
    scannf("%s%d%f",ptr->name,ampercent ptr->number,
             ampercent ptr->price);
    printf("\n  OUTPUT\n\n");
    ptr=product;
    while(ptr lessthan product+3)
    {
      printf("% -20s %5d %102f\n",ptr->name,
              ptr->number,ptr->price);
      ptr++;
    }
  }


 Output:
 INPUT
     Washing-machine 5  7500
     Electric-iron   12 350
     Two-in-one      7  1250

 OUTPUT:
     Washing-machine  5  7500.00
     Electric-iron    12 350
     Two-in-one       7  1250.00

While using structure pointers, we should take care of the precedence of operators.  The operators '->', '.',(),[] enjoy higher priority among the operators.They  bind very tightly with thier operands
 For example,given the definition
     struct
          {
            int count;
            float *p;
            *ptr
          }
 then the statement ++ptr->count; increments count,not ptr however,(++ptr)->count; increments ptr first,and then links count the statement ptr++->count;increments ptr first,and then links count the statement ptr++->count; is legal and increments ptr after accessing count.The following statements also behave in the similar fashion.*ptr->p   Fetches whatever p points to *ptr-p++  Increments p after accessing what ever it points to (*ptr->p)++  Increments  whatever p points to *ptr++->p Increments ptr after accessing whatever it points to.Passing of a structure as an argument to a function or a
function recieves a copy of an entire structure and returns it after working on it.This method is inefficient in terms of both.The execution speed and memory. We can overcome this drawback by passing a pointer to the structure and then using this pointer to work on the structure members.Consider the following function:
     Print_invent(item)
     struct invent *item;
     { printf("Name:%s\n",item->name);
        printf("price:%f\n",item->price);
     }
   this function can be called by
     print_invent(&product)
   The ormal argument item recieves the address of the structure product an therefore it must be declared as a pointer of type struct invent,which represents the structure of product.